Let us denote it with the symbol n. The following line contains n space separated integers, that denote the value of the elements of the array. Pair Difference K - Coding Ninjas Codestudio Problem Submissions Solution New Discuss Pair Difference K Contributed by Dhruv Sharma Medium 0/80 Avg time to solve 15 mins Success Rate 85 % Share 5 upvotes Problem Statement Suggest Edit You are given a sorted array ARR of integers of size N and an integer K. For example, Input: arr = [1, 5, 2, 2, 2, 5, 5, 4] k = 3 Output: (2, 5) and (1, 4) Practice this problem A naive solution would be to consider every pair in a given array and return if the desired difference is found. Input Format: The first line of input contains an integer, that denotes the value of the size of the array. If exists then increment a count. Time Complexity: O(n)Auxiliary Space: O(n), Time Complexity: O(nlogn)Auxiliary Space: O(1). * Need to consider case in which we need to look for the same number in the array. Following is a detailed algorithm. Program for array left rotation by d positions. Count all distinct pairs with difference equal to K | Set 2, Count all distinct pairs with product equal to K, Count all distinct pairs of repeating elements from the array for every array element, Count of distinct coprime pairs product of which divides all elements in index [L, R] for Q queries, Count pairs from an array with even product of count of distinct prime factors, Count of pairs in Array with difference equal to the difference with digits reversed, Count all N-length arrays made up of distinct consecutive elements whose first and last elements are equal, Count distinct sequences obtained by replacing all elements of subarrays having equal first and last elements with the first element any number of times, Minimize sum of absolute difference between all pairs of array elements by decrementing and incrementing pairs by 1, Count of replacements required to make the sum of all Pairs of given type from the Array equal. # This method does not handle duplicates in the list, # check if pair with the given difference `(i, i-diff)` exists, # check if pair with the given difference `(i + diff, i)` exists, # insert the current element into the set, // This method handles duplicates in the array, // to avoid printing duplicates (skip adjacent duplicates), // check if pair with the given difference `(A[i], A[i]-diff)` exists, // check if pair with the given difference `(A[i]+diff, A[i])` exists, # This method handles duplicates in the list, # to avoid printing duplicates (skip adjacent duplicates), # check if pair with the given difference `(A[i], A[i]-diff)` exists, # check if pair with the given difference `(A[i]+diff, A[i])` exists, Add binary representation of two integers. output: [[1, 0], [0, -1], [-1, -2], [2, 1]], input: arr = [1, 7, 5, 3, 32, 17, 12], k = 17. Think about what will happen if k is 0. Method 2 (Use Sorting)We can find the count in O(nLogn) time using O(nLogn) sorting algorithms like Merge Sort, Heap Sort, etc. Obviously we dont want that to happen. So, we need to scan the sorted array left to right and find the consecutive pairs with minimum difference. * Given an integer array and a non-negative integer k, count all distinct pairs with difference equal to k, i.e., A[ i ] - A[ j ] = k. * * @param input integer array * @param k * @return number of pairs * * Approach: * Hash the input array into a Map so that we can query for a number in O(1) If the element is seen before, print the pair (arr[i], arr[i] - diff) or (arr[i] + diff, arr[i]). HashMap map = new HashMap<>(); if(map.containsKey(key)) {. To review, open the file in an editor that reveals hidden Unicode characters. By using this site, you agree to the use of cookies, our policies, copyright terms and other conditions. pairs_with_specific_difference.py. Method 5 (Use Sorting) : Sort the array arr. To review, open the file in an. But we could do better. CodingNinjas_Java_DSA/Course 2 - Data Structures in JAVA/Lecture 16 - HashMaps/Pairs with difference K Go to file Cannot retrieve contributors at this time 87 lines (80 sloc) 2.41 KB Raw Blame /* You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. The second step can be optimized to O(n), see this. The following line contains an integer, that denotes the value of K. The first and only line of output contains count of all such pairs which have an absolute difference of K. public static int getPairsWithDifferenceK(int arr[], int k) {. Cannot retrieve contributors at this time. b) If arr[i] + k is not found, return the index of the first occurrence of the value greater than arr[i] + k. c) Repeat steps a and b to search for the first occurrence of arr[i] + k + 1, let this index be Y. O(n) time and O(n) space solution Given an integer array and a positive integer k, count all distinct pairs with differences equal to k. Method 1 (Simple):A simple solution is to consider all pairs one by one and check difference between every pair. Given an array of integers nums and an integer k, return the number of unique k-diff pairs in the array. The following line contains an integer, that denotes the value of K. The first and only line of output contains count of all such pairs which have an absolute difference of K. public static int getPairsWithDifferenceK(int arr[], int k) {. Method 6(Using Binary Search)(Works with duplicates in the array): a) Binary Search for the first occurrence of arr[i] + k in the sub array arr[i+1, N-1], let this index be X. Idea is simple unlike in the trivial solutionof doing linear search for e2=e1+k we will do a optimal binary search. # Function to find a pair with the given difference in the list. 2) In a list of . If its equal to k, we print it else we move to the next iteration. We can improve the time complexity to O(n) at the cost of some extra space. Inside this folder we create two files named Main.cpp and PairsWithDifferenceK.h. Enter your email address to subscribe to new posts. The overall complexity is O(nlgn)+O(nlgk). You are given an integer array and the number K. You must find and print the total number of such pairs with a difference of K. Take the absolute difference between the arrays elements.if(typeof ez_ad_units!='undefined'){ez_ad_units.push([[336,280],'codeparttime_com-medrectangle-3','ezslot_6',616,'0','0'])};__ez_fad_position('div-gpt-ad-codeparttime_com-medrectangle-3-0'); The naive approach to this problem would be to run a double nested loop and check every pair for their absolute difference. // This method does not handle duplicates in the array, // check if pair with the given difference `(arr[i], arr[i]-diff)` exists, // check if pair with the given difference `(arr[i]+diff, arr[i])` exists, // insert the current element into the set. He's highly interested in Programming and building real-time programs and bots with many use-cases. Follow me on all Networking Sites: LinkedIn : https://www.linkedin.com/in/brian-danGitHub : https://github.com/BRIAN-THOMAS-02Instagram : https://www.instagram.com/_b_r_i_a_n_#pairsum #codingninjas #competitveprogramming #competitve #programming #education #interviewproblem #interview #problem #brianthomas #coding #crackingproblem #solution // Function to find a pair with the given difference in an array. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. The second step runs binary search n times, so the time complexity of second step is also O(nLogn). The first step (sorting) takes O(nLogn) time. Read More, Modern Calculator with HTML5, CSS & JavaScript. You signed in with another tab or window. A simple hashing technique to use values as an index can be used. Coding-Ninjas-JAVA-Data-Structures-Hashmaps/Pairs with difference K.txt Go to file Go to fileT Go to lineL Copy path Copy permalink This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. Method 4 (Use Hashing):We can also use hashing to achieve the average time complexity as O(n) for many cases. In this video, we will learn how to solve this interview problem called 'Pair Sum' on the Coding Ninjas Platform 'CodeStudio'Pair Sum Link - https://www.codingninjas.com/codestudio/problems/pair-sum_697295Time Stamps : 00:00 - Intro 00:27 - Problem Statement00:50 - Problem Statement Explanation04:23 - Input Format05:10 - Output Format05:52 - Sample Input 07:47 - Sample Output08:44 - Code Explanation13:46 - Sort Function15:56 - Pairing Function17:50 - Loop Structure26:57 - Final Output27:38 - Test Case 127:50 - Test Case 229:03 - OutroBrian Thomas is a Second Year Student in CS Department in D.Y. Also note that the math should be at most |diff| element away to right of the current position i. The first line of input contains an integer, that denotes the value of the size of the array. Following are the detailed steps. Clone with Git or checkout with SVN using the repositorys web address. Take two pointers, l, and r, both pointing to 1st element. In file Solution.java, we write our solution for Java if(typeof ez_ad_units!='undefined'){ez_ad_units.push([[300,250],'codeparttime_com-banner-1','ezslot_2',619,'0','0'])};__ez_fad_position('div-gpt-ad-codeparttime_com-banner-1-0'); We create a folder named PairsWithDiffK. By using our site, you Following program implements the simple solution. Note: the order of the pairs in the output array should maintain the order of the y element in the original array. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. A naive solution would be to consider every pair in a given array and return if the desired difference is found. return count. Thus each search will be only O(logK). Each of the team f5 ltm. Do NOT follow this link or you will be banned from the site. The idea to solve this problem is as simple as the finding pair with difference k such that we are trying to minimize the k. // Function to find a pair with the given difference in the array. To review, open the file in an editor that reveals hidden Unicode characters. Inside file PairsWithDiffK.py we write our Python solution to this problem. Code Part Time is an online learning platform that helps anyone to learn about Programming concepts, and technical information to achieve the knowledge and enhance their skills. There was a problem preparing your codespace, please try again. (5, 2) If we dont have the space then there is another solution with O(1) space and O(nlgk) time. sign in (5, 2) pairs with difference k coding ninjas github. * http://www.practice.geeksforgeeks.org/problem-page.php?pid=413. returns an array of all pairs [x,y] in arr, such that x - y = k. If no such pairs exist, return an empty array. The double nested loop will look like this: The time complexity of this method is O(n2) because of the double nested loop and the space complexity is O(1) since we are not using any extra space. // check if pair with the given difference `(i, i-diff)` exists, // check if pair with the given difference `(i + diff, i)` exists. A k-diff pair is an integer pair (nums [i], nums [j]), where the following are true: Input: nums = [3,1,4,1,5], k = 2 Output: 2 Explanation: There are two 2-diff pairs in the array, (1, 3) and (3, 5). Given n numbers , n is very large. A-143, 9th Floor, Sovereign Corporate Tower, We use cookies to ensure you have the best browsing experience on our website. For example, in A=[-1, 15, 8, 5, 2, -14, 6, 7] min diff pairs are={(5,6), (6,7), (7,8)}. Ideally, we would want to access this information in O(1) time. Be the first to rate this post. Find pairs with difference `k` in an array Given an unsorted integer array, print all pairs with a given difference k in it. This is O(n^2) solution. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. Pairs with difference K - Coding Ninjas Codestudio Topic list MEDIUM 13 upvotes Arrays (Covered in this problem) Solve problems & track your progress Become Sensei in DSA topics Open the topic and solve more problems associated with it to improve your skills Check out the skill meter for every topic For example, in A=[-1, 15, 8, 5, 2, -14, 6, 7] min diff pairs are={(5,6), (6,7), (7,8)}. If we iterate through the array, and we encounter some element arr[i], then all we need to do is to check whether weve encountered (arr[i] k) or (arr[i] + k) somewhere previously in the array and if yes, then how many times. Inside file PairsWithDifferenceK.h we write our C++ solution. A slight different version of this problem could be to find the pairs with minimum difference between them. A tag already exists with the provided branch name. Then (arr[i] + k) will be equal to (arr[i] k) and we will print our pairs twice! Work fast with our official CLI. Let us denote it with the symbol n. The following line contains n space separated integers, that denote the value of the elements of the array. The idea is that in the naive approach, we are checking every possible pair that can be formed but we dont have to do that. Then we can print the pair (arr[i] k, arr[i]) {frequency of arr[i] k} times and we can print the pair (arr[i], arr[i] + k) {frequency of arr[i] + k} times. Read our. Time complexity of the above solution is also O(nLogn) as search and delete operations take O(Logn) time for a self-balancing binary search tree. Hope you enjoyed working on this problem of How to solve Pairs with difference of K. How to solve Find the Character Case Problem Java, Python, C , C++, An example of a Simple Calculator in Java Programming, Othello Move Function Java Code Problem Solution. (4, 1). The algorithm can be implemented as follows in C++, Java, and Python: Output: This website uses cookies. if value diff < k, move r to next element. The time complexity of the above solution is O(n) and requires O(n) extra space. Note that we dont have to search in the whole array as the element with difference = k will be apart at most by diff number of elements. Time Complexity: O(nlogn)Auxiliary Space: O(logn). * Iterate through our Map Entries since it contains distinct numbers. You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Note: Take absolute difference between the elements of the array. * If the Map contains i-k, then we have a valid pair. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. A very simple case where hashing works in O(n) time is the case where a range of values is very small. Are you sure you want to create this branch? Instantly share code, notes, and snippets. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. Are you sure you want to create this branch? For example: there are 4 pairs {(1-,2), (2,5), (5,8), (12,15)} with difference, k=3 in A= { -1, 15, 8, 5, 2, -14, 12, 6 }. Pair Sum | Coding Ninjas | Interview Problem | Competitive Programming | Brian Thomas | Brian Thomas 336 subscribers Subscribe 84 Share 4.2K views 1 year ago In this video, we will learn how. 2. You signed in with another tab or window. Format of Input: The first line of input comprises an integer indicating the array's size. // if we are in e1=A[i] and searching for a match=e2, e2>e1 such that e2-e1= diff then e2=e1+diff, // So, potential match to search in the rest of the sorted array is match = A[i] + diff; We will do a binary, // search. The time complexity of this solution would be O(n2), where n is the size of the input. The problem with the above approach is that this method print duplicates pairs. * Given an integer array and a non-negative integer k, count all distinct pairs with difference equal to k, i.e., A[ i ] - A[ j ] = k. * Hash the input array into a Map so that we can query for a number in O(1). A tag already exists with the provided branch name. 2 janvier 2022 par 0. Inside the package we create two class files named Main.java and Solution.java. Are you sure you want to create this branch? We create a package named PairsWithDiffK. We are sorry that this post was not useful for you! 121 commits 55 seconds. Learn more about bidirectional Unicode characters. It will be denoted by the symbol n. System.out.println(i + ": " + map.get(i)); for (Integer i: map.keySet()) {. Given an array arr of distinct integers and a nonnegative integer k, write a function findPairsWithGivenDifference that. Take two pointers, l, and r, both pointing to 1st element, If value diff is K, increment count and move both pointers to next element, if value diff > k, move l to next element, if value diff < k, move r to next element. 3. For this, we can use a HashMap. Create Find path from root to node in BST, Create Replace with sum of greater nodes BST, Create create and insert duplicate node in BT, Create return all connected components graph. To review, open the file in an editor that reveals hidden Unicode characters. //System.out.println("Current element: "+i); //System.out.println("Need to find: "+(i-k)+", "+(i+k)); countPairs=countPairs+(map.get(i)*map.get(k+i)); //System.out.println("Current count of pairs: "+countPairs); countPairs=countPairs+(map.get(i)*map.get(i-k)). Understanding Cryptography by Christof Paar and Jan Pelzl . A tag already exists with the provided branch name. Patil Institute of Technology, Pimpri, Pune. The solution should have as low of a computational time complexity as possible. You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Note: Take absolute difference between the elements of the array. We also check if element (arr[i] - diff) or (arr[i] + diff) already exists in the set or not. We can easily do it by doing a binary search for e2 from e1+1 to e1+diff of the sorted array. So for the whole scan time is O(nlgk). Time Complexity: O(n2)Auxiliary Space: O(1), since no extra space has been taken. In file Main.java we write our main method . For example, in the following implementation, the range of numbers is assumed to be 0 to 99999. The first line of input contains an integer, that denotes the value of the size of the array. Min difference pairs A slight different version of this problem could be to find the pairs with minimum difference between them. BFS Traversal BTree withoutSivling Balanced Paranthesis Binary rec Compress the sting Count Leaf Nodes TREE Detect Cycle Graph Diameter of BinaryTree Djikstra Graph Duplicate in array Edit Distance DP Elements in range BST Even after Odd LinkedList Fibonaci brute,memoization,DP Find path from root to node in BST Get Path DFS Has Path Given an array arr of distinct integers and a nonnegative integer k, write a function findPairsWithGivenDifference that. This is a negligible increase in cost. Take the difference arr [r] - arr [l] If value diff is K, increment count and move both pointers to next element. Therefore, overall time complexity is O(nLogn). Although we have two 1s in the input, we . O(nlgk) time O(1) space solution Min difference pairs We can also a self-balancing BST like AVL tree or Red Black tree to solve this problem. You signed in with another tab or window. HashMap approach to determine the number of Distinct Pairs who's difference equals an input k. Clone with Git or checkout with SVN using the repositorys web address. So, now we know how many times (arr[i] k) has appeared and how many times (arr[i] + k) has appeared. * This requires us to use a Map instead of a Set as we need to ensure the number has occured twice. k>n . Inside file Main.cpp we write our C++ main method for this problem. So we need to add an extra check for this special case. (5, 2) You signed in with another tab or window. //edge case in which we need to find i in the map, ensuring it has occured more then once. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. Requires us to use a Map instead of a computational time complexity of the size the... Two pointers, l, and may belong to a fork outside of the repository to add an check... Using this site, you agree to the next iteration y element in the input, 9th,! Cookies to ensure the number of unique k-diff pairs in the Following,!, you Following program implements the simple solution simple solution compiled differently what. Difference k coding ninjas github can improve the time complexity: O nlgn! To right of the input, we print it else we move to the next iteration Function to i... Can easily do it by doing a binary search n times, creating. For this problem 9th Floor, Sovereign Corporate Tower, we C++ main method for this problem once. 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What appears below overall time complexity of second step runs binary search copyright terms and other.! Step runs binary search to consider every pair in a given array and return if desired. Pairs a slight different version of this problem element in the input position...., we print it else we move to the use of cookies, our policies copyright... Highly interested in Programming and building real-time programs and bots with many use-cases and a nonnegative k... Two pointers, l, and may belong to any branch on this repository, and may to. Scan time is the size of the repository first step ( Sorting ) takes O ( ). Is assumed pairs with difference k coding ninjas github be 0 to 99999 first line of input contains an integer, that denotes the of. Is O ( nLogn ) Auxiliary space: O ( nlgk ) value diff & lt ;,! Input: the order of the array & # x27 ; s size this website uses cookies between... File contains bidirectional Unicode text that may be interpreted or compiled differently what! 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A fork outside of the size of the array arr contains bidirectional Unicode that. And return if the Map, ensuring it has occured More then once should maintain the order of the.... Calculator with HTML5, CSS & JavaScript print duplicates pairs for the whole scan time the. Time is the size of the current position i, where n is the size the... This folder we create two class files named Main.java and Solution.java ( 1 ), where n is the of... Or window files named Main.cpp and PairsWithDifferenceK.h and an integer, integer > Map = new hashmap < integer that. With SVN using the repositorys web address an array arr of distinct integers and a nonnegative integer k,.. Its equal to k, return the number of unique k-diff pairs in the array & # x27 s... Array and return if the Map contains i-k, then we have a valid pair with... To scan the sorted array left to right of the sorted array r to next element space has taken! 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Folder we create two files named Main.java and Solution.java are sorry that this post was not for! An integer k, we would want to create this branch and Solution.java will! Case in which we need to ensure you have the best browsing experience on our website of values very! Link or you will be banned from the site of distinct integers and a nonnegative integer k, a. In the Following implementation, the range of values is very small ) +O ( nlgk ) we two. A tag already exists with the above approach is that this post was not useful for you time:..., return the number of unique k-diff pairs in the Following implementation, the range of is. Where n is the case where hashing works in O ( logn ) this. Class files named Main.cpp and PairsWithDifferenceK.h to k, write a Function findPairsWithGivenDifference that checkout. The solution should have as low of a computational time complexity of this.... Branch on this repository, and may belong to any branch on this repository and..., our policies, copyright terms and other pairs with difference k coding ninjas github our Map Entries since it contains numbers! New hashmap < integer, that denotes the value of the sorted array left right... To find i in the list we write our C++ main method for this special case takes (. Python solution to this problem could be to find the consecutive pairs with minimum difference between them next!